What is the standard form equation for a 1/2 line that passes though (-3,-3) and (4,2)

y= 5/7x -2.7

Step-by-step explanation:

Y= mx + c                             (-3,-3)   (4,2)

                                           x1  , y1     x2, y2

to find m (gradient)

y^2 - y^1 / x^2 - x^1

2-(-3) / 4 - (-3)

5/7                               m = 5/7

take (4,2)  and gradient and substitute

2=5/7(4) + c

2=4.7+ c

2-4.7 = c

-2.7 = c

now we have c and m so just put it in the equation

y= 5/7x -2.7

the fist one is not equalvalent but i think th second one isand the third isnt definetly or the last one is i think. hope this !

step-by-step explanation: