HELP PLEASE ! Write an equation of a line that passes through the point (4, 3) and is perpendicular to the graph of the equation y= -1/3x+4

y = 3x - 9

Step-by-step explanation:

✔️Find the slope of the line perpendicular to the given graph of equation:

A line that is perpendicular to the graph of the equation y = -⅓x + 4, will have a slope value that is the negative reciprocal of the slope of the graph of the given equation.

The slope of y = -⅓x + 4 is -⅓.

Negative reciprocal of -⅓ = 3

Slope of the line (m) = 3

✔️Find the y-intercept (b):

Substitute (x, y) = (4, 3) and m = 3 into y = mx + b

3 = 3(4) + b

3 = 12 + b

3 - 12 = b

-9 = b

b = -9

✔️Write the equation:

Substitute m = 3 and b = -9 into y = mx + b

y = 3x + (-9)

y = 3x - 9

answer: all the values are within because it has a pattern that repeats from -6 to 4.

good luck!

start with a line segment pq that we will copy. mark a point r that will be one endpoint of the new line segment. set the compasses' point on the point p of the line segment to be copied. adjust the compasses' width to the point q. the compasses' width is now equal to the length of the line segment pq.

step-by-step explanation: