Four biased coins, A, B, C and D are thrown. The probability that each coin will land on Heads is shown in the table.
Coin Probability a) (i) Which coin is least likely to land on Heads?
А
0.66
(1)
0.066
(ii) Which coin is most likely to land on Heads?
С
(1)
60%
b) What is the probability that D will land on Tails?
(1)
B
D
Coin B is going to be thrown 4000 times.
c) Work out an estimate for the number of times
coin B will land on Heads.
(2)
Total marks: 5

Please check explanations for answer

Step-by-step explanation:

Firstly, we need all the probability in the same decimal form

P(A) = 0.66

P(B) = 0.067

P(C) = 2/3 = 0.67

P(D) = 60/100 = 0.6

a) The least likely is the smallest value of decimal

This is 0.067 which is for coin B

most likely is the highest probability; this is C which is 2/3

b. Probability that D will land on tail is 1 - probability that it lands on head

= 1 - 0.6 = 0.4

c. Mathematically that is the product of the probability and the number of times it was thrown

That will be;

0.066 * 4000

= 264 times

its c or d   take a lucky guess my dude

step-by-step explanation:   divide the numerator by the denominator to get the decimal

it would still be 193

if divide by 100 then 1.93

i am not sure