A line with a slope of 0.20 passes through the point (1.25, -17.5). What is the
equation of the line in slope-intercept form?

Plss help ASAP I’ll give anything

y=0.2x-20

Step-by-step explanation:

1) the common view of the line in the slope-intercept form is:

y=s*x+i, where s - the value of the slope (it is 0.2 according the condition), i - the value of intercept (to be calculated);

y=0.2*x+i.

2) if to substitute the given coordinates (1.25;-17.5) into the common view, then:

-17.5=1.25*0.2+i;

it is possible to calculate the value of 'i': i= -20.

3) if the slope=0.2, the intercept= -20, then the required equation of the line is:

y=0.2x-20.

option 2 is correct.

step-by-step explanation:

we are given two inequality equation

x+y> 5 and -3x+2y< -2

first we draw the graph of both function using t-table method

equation: x+y> 5

for x=0, y=5

for x=-5, y=0

table:

x   :   0     5

y   :   5     0

test point (0,0) , 0> 5

false

equation: -3x+2y< -2

for x=0, y=-1

for x=2, y=4

table:

x   :   0     2

y   : -1       4

test point (0,0) , 0< -2

true

now we draw the graph. see the attachment for graph.

common region would be solution set.

option 2 is correct.

answer: 2x + 2 − 2 = 10 − 2; subtraction property of equality

step-by-step explanation: