Solve for x: (2/x-2) + (7/x^2-4) = (5/x)

a. x = -(4/3) and x = 5
b. x = (4/3) and x = 5
c. x = (4/3 and x = _5
d. x = -(4/3) and x = _5
!

The equation given in the question is

(2/x - 2) + (7/x^2 - 4) = (5/x)
(2/x-2) + (7/(x + 2)(x - 2) = (5/x)
2(x + 2) + 7/(x+ 2)(x - 2) = 5/x
(2x + 4 + 7)/(x + 2) (x - 2) = 5/x
(2x + 11)x = 5x^2 - 20
2x^2 + 11x = 5x^2 - 20
5x^2 - 2x^2 - 11x - 20 = 0
3x^2 - 11x - 20 = 0
(3x + 4) (x - 5) = 0
Either 
x = -4/3
or
x = 5
From the above deduction, it can be easily concluded that the correct option among all the options that are given in the question is the first option or option "a".

Skew lines(segments) are lines(segments) in 3 dimensions that do not intersect the given segment and are not parallel to it.  ae, bf, eg, and fh are your skew segments.  i hope that : )