In the given figure PQRS , SP = RQ and RP = SQ . Prove that RT = ST. ~Thanks in advance !

in triangle spq and pqr

pq=pq (common side)

sp=rq(given)

sq=rp(given)

triangle spq is congruent to pqr by S.S.S. axiom

in triangle pts and qtr

PS=qr (given)

<STP=<rtq(vertically opposite angle)

<PST=<prq(corresponding angle of congruent triangle are equal )

triangle stq is congruent to rtq by S.A.A.axiom

than

rt=st ( side of congruent triangle are equal)

proved

step-by-step explanation:

because 1/3 is a fraction. we can tell because there is a divisor symbol between the 1 and the 3. if we were to add 2 fractions together, we would add the numerators, which is the number on top, but not the denominators, which is the number on the bottom

1/3+1/3=2/3

hope this !

option (b) is correct

step-by-step explanation:

to find the solution of this system, we need to convert it into reduced row-echelon form. we have,

after applying row operations r2 -> r2/2 and r3 -> r3/3, we get,