1c - 20 = 4 - 3c pls help fast in school rn

4c-20= 4

+20  +20

4c= 24

/4 /4

c= 6

c = 1 btw can i be brainiest...

Step-by-step explanation:

First, rewrite the left side of the equation and group and combine like terms:

c + (4 − 3c) − 2 = 0

c + 4 − 3c − 2 = 0

−3c + c + 4 − 2 = 0

−3c + 1c + 4 − 2 = 0

(−3 + 1) c + (4 - 2) = 0

−2c + 2 = 0

Next, subtract

2

from each side of the equation to isolate the

c

term while keeping the equation balanced:

−2c + 2 − 2 = 0

−2 − 2c + 0 = −2

−2c = −2

Now, divide each side of the equation by

−2

to solve for

c

while keeping the equation balanced:

−2c - 2 = −2 − 2

−2c − 2 = 1

c = 1

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺