Which equation could be used to solve for the length of side c, given a = 5, b = 12, and C = 72°?

law of cosines

c^2=(5)^2+(12)^2-2(5)(12)cos72

i had this question before

Step-by-step explanation:

c^2=a^2+b^2-2abcos(c)

c=sqrt(a^2+b^2-2abcos(c))

c=sqrt((5)^2+(12)^2-2(5)(12)cos(72))

c=sqrt(25+144-120cos(72))

c=sqrt(169-120cos(72))

c=sqrt(169-37.08)

c=sqrt(131.92)

c=11.49

the median here is 25. your lowest value is 14 and highest value is 48. to find the third quartile, find the medium number in between 25 and 48 which would be 42 i believe.

step-by-step explanation: