Which shows the solution of the combined inequality? −1≤2−j<−5

Number line ranging from negative six to zero with a line beginning with an open point at negative five and ending with a closed point at negative one

Number line ranging from negative six to zero with a line beginning with a closed point at negative five and ending with an open point at negative one

Number line ranging from zero to six with a line beginning with a closed point at one and ending with an open point at five

no solution

step-by-step explanation:

answer: it is a.,b.,d.

step-by-step explanation:

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.

answer: can you show the options ?

step-by-step explanation: