The sum of four consecutive integers is 170. Write an equation that can be used to find the smallest integer.

The Equation to find the smallest integer =

4x + 6 = 170

The smallest integer = First integer = x = 41

Step-by-step explanation:

Four consecutive integers is represented by:

First Integer = x

Second Integer = x + 1

Third Integer = x + 2

Fourth Integer = x + 3

The sum of four consecutive integers is 170.

x + x + 1 + x + 2 + x + 3 = 170

The Equation to find the smallest integer =

4x + 6 = 170

4x = 170 - 6

4x = 164

x = 164/4

x = 41

Therefore:

The Equation to find the smallest integer =

4x + 6 = 170

The smallest integer = First integer = x = 41

fist on the left goes with the third on the right. second on the left goes with the fourth on the right. third on the left goes with the second on the right. the fourth on the left goes with first on the right

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752