Please helpp ah

c. a = 3√2, b = 6√2

#1.First, you find the opposite of the left triangle using sin formula

#2.After you get the opposite, find the b using sin formula and a using tan formula

•Right triangle

Hypotenuse = 6

Adjacent = ?

Opposite = ?

• Left triangle

Hypotenuse = b

Adjacent = a

Opposite = ?

a. adjacent of right triangle

b. hypothenuse of left triangle

#1. Sin(∅)= opposite/hypotenuse

sin(45) = opposite/6

opposite = sin(45) × 6

opposite = 3√2

#2. a. tan(∅) = opposite/adjacent

tan(30) = 3√2 / a

a = 3√2 : tan(30)

a = 3√6

b. sin(∅) = opposite/hypotenuse

sin(30) = 3√2 / b

b = 3√2 : sin(30)

b = 6√2

#and so the a = 3√2 and b = 6√2

#you are welcome

#Moderators please don't be mean, dont delete my answers just to get approval from your senior or just to get the biggest moderation daily rank.

i am sorry it just submitted an answer but the answer is 365 boys. hopes this

step-by-step explanation:

answer: evaluate the objective function at each vertex to determine which - and -values, if any, maximize or minimize the function. example: find the minimum value and maximum value of the objective function f ( x , y ) = 4 x + 5 y , subject to the following constraints