The length of a rectangle is 3 more than twice the width. the area of the rectangle is 119 square inches. what are the dimensions of the rectangle? if x = the width of the rectangle, which of the following equations is used in the process of solving this problem?

If x is the width, and the length is 3 more than twice the width,
the length : 2x+3

Area = length x width

(2x+3)x = 119
By expanding equation,  = 119
Thus,  
By factorisation, 
(x-7)(2x+17)= 0
x=7 or x= -17/2 (rejected because width cannot be negative)

Thus, the width is 7 and the length is 2(7) +3 = 17

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