9. Verify that APQR - ASQT. A ZQ = 2Q by the Reflexive Property of Congruence.
OS QT
QP OR
APQR - ASQT by SAS Similarity.
B ZQ E ZQ by the Reflexive Property of Congruence.
PS QT
OP
APQR - ASQT by SAS Similarity.
CZP = 2QTS and ZRE ZQST by the Alternate Interior Angles Theorem.
APQR - ASQT by AA Similarity.
D ZP = ZQST and ZRE ZQTS by the Corresponding Angles Postulate.
APQR - ASQT by AA Similarity.
OR = }
Choose

can you complete your sentence? i could !

sorry

step-by-step explanation:

sorry, but im pretty sure its a now that i look at it

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.

1) the property is   ixi = a ⇔x = a   o x = -a

4(x-5)+3= 15⇒4x-20+3 = 15⇒4x-17= 15⇒4x = 15+17⇒4x = 32⇒x =32/4= 8

4(x-5) +3= -15⇒4x-20 +3 = -15⇒4x-17= -15⇒4x =-15+17⇒4x = 2⇒x =2/4= 1/2

the values are x =8 and x = 0,5