1.2 PRUEBA DIAGNOSTICO David tiene dos sustancias con las propiedades que se registran en la siguiente tabla
Si David se encuentra en una ciudad de tierra caliente, con una temperatura de 25 C. cual es el
estado de la materia de cada sustancia?
A Sustancia i gaseoso sustancia 2 sólido.
B. Sustancia 1: liquido: sustancia 2 gaseoso
Sustancia i solido, sustancia 2: liquido
D. Sustancia 1 gaseoso sustanca 2 liquido.​

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

2 x 503

step-by-step explanation:

its 1006

answer: 5

step-by-step explanation:

since, the range is the difference between the lowest and highest values of the given sample space.

and, here the sample space = { 3, 1, 0, 4, 1, 4, 2, 3, 0, 5, 0, 1, 1, 2, 0, 4, 1,4, 4 ,2 ,3 ,2 ,0 ,1 ,4 }

here, the highest value of the given sample = 5

and, the lowest value = 0

therefore, the range of the sample space = 5 - 0 = 5