The perimeter of a rectangular field is 340 yd. The length is 50 yd longer than the width. Find the dimensions.

width = 60 yd

and Length= 110 yd

Step-by-step explanation:

Step 1

Perimeter of rectangle field  is given as  2 ( L+ b)

Let the width be represented as x

'and length which is  50 yd longer than the width be

=x+ 50

such that the Perimeter with 340 yd can be expressed as

Perimeter = 2 ( L+ b) = 2L + 2B

Step 2---Solving

Perimeter = 2L + 2B

340 = 2(X+ 50) + (2 x)

340 = 2X+ 100 + 2X

340=4X + 100

340-100=4X

240= 4X

X= 240/4

X= 60

Width = x = 60 yards

 ;Length = 50 + x= 50 + 60 = 110yards

Width=60 yd

length=110 yd

Step-by-step explanation:

80π/3 or about 83.775

step-by-step explanation:

since a cone is 1/3 of a cylinder, we need to find the base's area. since area = πr^2, we get 16π. then, multiplying this by 5, we get 80π. dividing by 3, since the cone's volume is 1/3 of that of a cylinder's, we get 80π/3.

hope this !