The second hand on Mr. Vidler's Alarm Clock is 6 cm long. Approximately how far does the tip travel in 5 minutes and 15 seconds? [Round your answer to the nearest tenth. Only type in the number, no units.]

3.28 cm

Step-by-step explanation:

The computation is shown below:

The Radius of a circle be R

And, An arc be A

So, the length of the arc would be

L = (A ÷ 360°) × 2 × 3.14 × R

Here R = 6 cm

Angle = 5 minutes and 15 seconds

As we know that the clock has the complete revolution in 60 minutes

So  

60 minutes = 360°

As we know that

60 seconds = 1 min

 So,

1 = 1min ÷ 60seconds  

15 seconds = 15 seconds × ((1 ÷ 60)

= (15 ÷ 60) min

= 0.25 min

So,

5 minutes and 15 seconds

= 5 min + 0.25 min

= 5.25 min

60 minutes = 360°

So,  

1 = 360° ÷ 60min

For  5.25min

= (5.25min) × (360° ÷ 60min)

= 31.5°

Then we have A = 31.5°

Now the far would be  

L = (31.5° ÷ 360°) × 2 × 3.14 × 6cm

= 3.28 cm

i can answer this question sweetie!

step-by-step explanation:

1. 3.4/4

2. 0.8/7

3. 0.5 x 3

4. 0.9 x 6

5. 10.8

6. 2.35

7. 0.567

8. 9.35

9. 0.02

10. 0.06

11. 0.16

12. 0.42

13. 0.63

14. 5.6

15. 8.1

16. 9.9

17. 0.28

18. 0.48

19. 0.27

20. 0.49

21. 0.45

22. 0.72

23. 0.9

24. 0.88

25. 0.75

26. 0.16

27. 0.328

28. 0.495

29. 0.72

30. 1.068