2sin 2A - sin 4A
2sin 2A + sin 4A
= tan²A​

tan²A - sin²A = tan² A sin²A

from LHS,

tan²A -sin²A

= (sin²A / cos²A) - sin²A……[tan A=sin A/cos A]

= (sin²A - sin²Acos²A) / cos²A

= sin²A (1- cos²A) / cos² A [tan A = sinA / cos A]

= tan²A sin²A= RHS

.•. hence proved

Step-by-step explanation:

Hope it is helpful...

the answer is:

the answer is:

to solve the problem, we need to remember the quotient of power property, it's defined by the following relation:

if we have a quotienf of powers that have the same base, we need to keep the same base and subtract the exponent of the denominator power to the exponent of the numerator power.

so, we are given the expression:

then, calculating we have:

hence, the answer is:

have a nice day!

answer: the answer is d