Solve this equation using synthetic division x³+2x²+4x+8=0​

Your answer is

x^3 + 2x^2 + 4x + 8=0 Note.. if x=-2 then whole equation is 0

So, (x+2) is one factor.

x^3 + 2x^2 + 4x + 8

=x^2(x+2)+4(x+2)

(x+2)(x^2+4)

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false

step-by-step explanation:

4y - 6 + 4y^2 - 9

before simplifying this contains 4 terms

after simplifying

4y -15 + 4y^2

it contains 3 terms

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

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