I need some help, please. I need to determine the slope and y-intercept for each group. I need to write the equation for the graph in slope-intercept form.

Slope: 0

A horizontal line's slope is 0.

Y-intercept: (0,-3)

The y-intercept is the pint where the line crosses the y axis

equation: y=-3

I wrote it in the y=mx+b format.

m is slope, b is the y-intercept

the is equation y=0x-3, but since 0x=0, I didn't need to write it.

Another way to look at it is that no matter what x is, y is always -3

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180