What is the equation of a line that has a slope of -5 and passes through the point (0, 2)? y = -5x
y = 2x - 5
y = -5x + 2

y= -5x+2 is the equation.

y= -5x + 2

Step-by-step explanation:

y = mx + b(we will put the points of "x" and "y" into this formula)

2= -5 (0) +b( as "x" is "0" and is multiplied by "-5" it will become "0" giving us the value of "b")

2=b(finally we will substitute this answer in the formula we've written)

therefore the answer will be:

y= -5x + 2

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i