A rectangle measures 8.5 cm by 10.7 cm both correct to 1 decimal place. Calculate the upper bound of the perimeter of the rectangle​

The perimeter of the rectangle = 38.4cm

Step-by-step explanation:

Explanation:-

Given that the length of the rectangle(l) = 8.5cm

The width of the rectangle(w) = 10.7cm

The perimeter of the rectangle

                 P = 2(l+w)

                P = 2( 8.5 + 10.7)

                P = 2 ×19.2 = 38.4 cm

The perimeter of the rectangle = 38.4cm

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

idk

step-by-step explanation: