Line segment JK has endpoints at J(-3,4) and K(3,6). Which is an equation of a line that is perpendicular to line segment JK and passes through the point (3,-12)

y = -3x - 3.

Step-by-step explanation:

Find the slope of the line JK:

Slope = (6-4)/(3- (-3))

= 2 / 6

= 1/3.

Therefore the slope of the line perpendicular to it is - 1 / 1/3

= -3.

Now we use the point-slope form of a line to get the required equation:

y - y1 = m(x - x1)

Here m = -3 and (x1, y1) = (3, -12) so we have

y - (-12) = -3(x - 3)

y + 12 = -3x + 9

y = -3x + 9 - 12

y = -3x - 3 is the answer.

divide by 5

step-by-step explanation:

60/5 = 12

the multiples of 15 are 15, 30,45, 60, 75, 90, 105, 120, 135, 150, 165, 180, 195,   210, 225, 240, 255, 270, 285, 300, 315, 330, 345, 360, 375,   390, 405, 420, 435, 450, 465, 480, 495, 510, 525, 540, 555, 570, 585, 600, 615, 630, 645, 660, 675, 690, 705, 720, and 735.

the factors of 15 are 1, 3, 5, and 15.

hope that , fam!

-une, your fren : )