R, S, Q and P are the midpoints of OC, CB, BA and OA respectively. OR = a, CS = b and OP =C

Show that RS is parallel to PQ

Note: Ignore arrows above vectors eg write RS, not RS

+

B

P

С

S

b

O

a

R

26

NW

P

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

you need to upload the picture of the circle.

step-by-step explanation: