Suppose a certain character in a role-playing game has an ability to use in battles. When activated, the ability deals damage to an enemy using X hits, where X is a random variable with the following cumulative distribution function The chance of getting between 2 and 4 hits is 0.46 . The chance of getting exactly 3 hits is

The chance of getting exactly 3 hits is =  0.20

Step-by-step explanation:

P.S - The exact question is -

As given,

F(x) = 0 ,          x < 1

         0.30 ,     1  ≤ x < 2

         0.56 ,     2 ≤ x < 3

         0.76 ,     3 ≤ x < 4

         0.9 ,       4  ≤ x < 5

         1 ,            5  ≤ x

Now,

f(x) = 0.30 ,                            x = 1

        0.56 - 0.30 = 0.26 ,     x = 2

         0.76 - 0.56 = 0.20 ,     x=3

         0.9 - 0.76 = 0.14  ,       x = 4

         1 - 0.9 = 0.1 ,                 x = 5

          0,                                 otherwise

Now,

The chance of getting exactly 3 hits is = f(x = 3) = 0.20

21

jk it's 20

step-by-step explanation:

not sure but it may be b, as i said i'm not sure.