Find the second derivative of the function.

Answer

The second derivative of an implicit function can be found using sequential differentiation of the initial equation F(x,y)=0. At the first step, we get the first derivative in the form y′=f1(x,y). On the next step, we find the second derivative, which can be expressed in terms of the variables x and y as y′′=f2(x,y).

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

cant open file sorry!

step-by-step explanation: