What is the equation of the line that passes through (-3, -1) and has a slope of 3/5 ? Put your answer in slope-intercept form. y = 3/5x + 4/5
y = -3/5 x - 4/5
y = 3/5x - 4/5

y=3/5x+4/5A

I hoped this helped

THE ANSWER IS: y = 3/5 + 4/5

first plug the slope and the given point into point-slope from: (y-y1) = m (x-x1)
m=slope= 3/5
point=(x1,y1) = (-3,-1)

(y+1) = 3/5 (x+3)
solve for y to get slope-intercept form
y+1 = 3/5x + 9/5
y = 3/5x + 4/5

21/2 or 5/2