Given quadrilateral ABCD, find the values for x and y. x = 4, y = 6

x = 34, y = 56

x = 1067, y = 223

x = 627, y = 1109

x = 4, y = 6

Step-by-step explanation:

Consider the triangle BEC.

∠BEC=112 (vertically opposite angles)

∠EBC=∠ECB (BEC is an isosceles triangle)

All the angles in a triangle add up to 180, so:

∠BEC+∠EBC+∠ECB=180

112+(7x+6)+(7x+6)=180

14x=180-112-6-6

x=56/14=4

Consider the triangle CED

∠CED=68 (lies on a straight line with 112, angles on a straight line add up to 180)

∠EDC=∠ECD (CED is an isosceles triangle)

All the angles in a triangle add up to 180, so:

∠CED+∠EDC+∠ECD=180

68+(9y+2)+(9y+2)=180

18y=180-68-2-2

y=108/y=6

X = 4 , y = 6

Step-by-step explanation:

a 270° rotation about point p says on e d g e n u it y (had to space it out because it says it's a misspelling so i couldn't submit it

many reason,

step-by-step explanation: