The length of a rectangle is 6cm longer than the width, and the perimeter is at least 48 cm. Write and solve an inequality to determine the smallest possible dimensions.

step-by-step explanation: i dont

you can use a^2+ b^2=c^2

1st integer x

2nd integer x+1

3rd integer x+2

4th integer x+3

x+x+1 +x+2+x+3 =74

combine like terms

4x+6 = 74

subtract 6 from each side

4x = 68

x = 17

the integers are 17,18,19,20