In the diagram below, BC = QR = x, AC = PR y, and triangle PQR is a right triangle. Use the drop-down menus to complete the proof that if the equation
2? + y = z2 is true of the side lengths in triangle ABC, then triangle ABC must be a right
triangle.
P
X
B
x2 + y2 = 22
Triangle PQR is a right triangle
Click the arrows to choose an answer from each menu.
Triangle PQR is given to be a right triangle, so the Pythagorean theorem can be used to
determine that choose...
It is given that x2 + y2 = z2 in triangle ABC, so
Choose...
This information shows that the triangles are congruent
because their three sides are congruent. Therefore, to show that triangle PQR is a right triangle,
we can use corresponding parts of the congruent triangles to show that Choose..
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huh? im pretty sure it is in 199

step-by-step explanation:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!

step-by-step explanation:

consider the parallelogram shown in the attached image.

in the parallelogram hijk, the length of hk is given as,

from the properties of parallelogram we know that the opposite sides of a parallelogram are parallel to each other and are equal in measure.

therefore, the length of the side ij must be equal to the length of the side hk and that is .

hence, the expression for the length of ij confirms that hijk is a parallelogram.

this "question" looks more like a project is there any other info you can give me about this. it could be too complex for someone else to do on this website