Write an equation for the nth term of the geometric sequence 2, 8, 32, 128,

2^(1+2n)

2^(1+0) = 2
2^(1+2) = 2^3 = 8
2^(1+4) = 2^5 = 32

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answer:
congruent segments
step-by-step explanation:
congruent segments. take a line, cut it in half, superipose one half over the other half; you'll have congruence.