A teacher purchased 20 calculators and 10 measuring tapes for her class and paid $495. Later, she realized that she didn't order enough supplies. She placed another order of 8 of the same calculators and 1 more of the same measure tape and paid $178.50.The system represents the situation `20c+10m=495`

`8c+1m=178.50`

Find the cost of one calculator and the cost of one measure tape using one of our methods of solving systems.

Equations are

20c + 10m = 495(1)

8c + 1m = 178.5(2)

Now ,  equation (2) * 10 = 80c + 10m = 1785(3)

So, Eq. (3) -  Eq(1) =

80c + 10m - 20c - 10m = 1785 - 495

60c = 1290

c= 21.5

Now place the value of c in Eq (2)

So , m =6.5

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