What are the lengths of the legs of a right triangle in which one acute angle measures 19° and the hypotenuse is 15 units long? OA 9 units, 12 units
OB. 11 units, 10.2 units
OC 4.9 units, 15.8 units
OD 4.9 units, 14.2 units
OE 5.2 units, 14.1 units

D) 4.9 units, 14.2 units

Step-by-step explanation:

I assume that we will be using trigonmetry as this is a right triangle

The two ratios that will be used are CAH (Cosine = adjacent/hypotneuse)

and SOH (Sine = opposite/hypotneuse)

While it does not matter which acute angle the problem is to, I decided to set up the triangle like so in the picture attached

This means x = adjacent and y = opposite here

Now we just need to plug in the numbers to find the missing variables

x) cos(19) = x/15

(15)cos(19) = x/15(15)

~14.2 = x

y) sin(19) = y/15

(15)sin(19) = y/15(15)

~4.9 = y

Hope that helps a bit

I took waaay too long to explain this lol

i dont know

step-by-step explanation:

umm. i dont know