2, 6, 18, 54. 162,... The first five terms of a geometric sequence are given above.

Write a recursive function rule for the sequence.

a
f\left(n\right)=3f\left(n\right)+2< br />
b
f\left(n\right)=2n

c
f\left(n\right)=3f\left(n-1\right), \ n1=2

d
f\left(n\right)=3n+2

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Step-by-step explanation:

The first term is 2, so part of the recursive definition is ...

  f(1) = 2

The common ratio is 6/2 = 3, so each term is 3 times the previous one. That part of the recursive definition is ...

  f(n) = 3·f(n -1)

These two parts of the definition match choice C.

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step-by-step explanation:

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)