What is the solution to the system of equations2x + 3y = 40andy=x + 10? A
x = 2; y = 12
B
x = 4; y = 14
C x = 12; y = 2
D x = 14; y = 4

A is the correct answer

Step-by-step explanation:

If you plug y=x+10 in for the Y variable you just have to solve by multiplying.

1.) It should look like this:

2x + 3(x +10) = 40

2.) You will distribute the three which will make the equation look like this:

2x + 3x + 30 = 40

3.) Add like terms. Then subtract 30 from both sides. Then divide 5 by both sides to get the variable x alone.

Hope that helps

A is the correct answer is the correcta answer

If you plug y=x+10 in for the Y variable you just have to solve by multiplying.

1.) It should look like this:

2x + 3(x +10) = 40

2.) You will distribute the three which will make the equation look like this:

2x + 3x + 30 = 40

3.) Add like terms. Then subtract 30 from both sides. Then divide 5 by both sides to get the variable x alone.

the expected value of the random variable : 0, 1 and 2

step-by-step explanation: