The difference of 8 and six times a number is a minimum of sixty-eight

Let's represent the unknown number with the variable, x.

The word "difference" indicates subtraction and "times" indicates multiplication.

The "difference of 8 and six times a number" would be represented as:  8 - 6x

NOTE: The order of the terms is important (8- 6x is not the same as 6x - 8).

This expression 8 - 6x must be at least 68 to meet the requirement of being at least a "minimum".

The final inequality will be:   8 - 6x  ≥ 68

Step-by-step explanation:

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-6

Step-by-step explanation:

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step-by-step explanation:

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.