Given points M(1,2), N(4,4), P(5,−1), J(−7,−1), K(−1,3), and L(1,−7), which of the following proves that △MNP≈△JKL? By the Distance Formula, MN=13, NP=26, and PM=25.Also, JK=52, KL=104, and LJ=100.Therefore, MNJK=NPKL=PMLJ=14, andtherefore, △MNP∼△JKL by SSS ∼.

By the Distance Formula, MN=13, NP=26, and PM=25.Also, JK=52, KL=104, and LJ=100.Therefore, MNJK=NPKL=PMLJ=14, andtherefore, △MNP∼△JKL by SAS ∼.

By the Distance Formula, MN=13−−√, NP=26−−√, and PM=5.Also, JK=213−−√, KL=226−−√, and LJ=10.Therefore, MNJK=NPKL=PMLJ=12, andtherefore, △MNP∼△JKL by SSS ∼.

By the Distance Formula, MN=13−−√, NP=26−−√, and PM=5.Also, JK=213−−√, KL=226−−√, and LJ=10.Therefore, MNJK=NPKL=PMLJ=12, andtherefore, △MNP∼△JKL by SAS ∼.

simplifying

5(x + -6) = 2(x + 3)

reorder the terms:

5(-6 + x) = 2(x + 3)

(-6 * 5 + x * 5) = 2(x + 3)

(-30 + 5x) = 2(x + 3)

reorder the terms:

-30 + 5x = 2(3 + x)

-30 + 5x = (3 * 2 + x * 2)

-30 + 5x = (6 + 2x)

solving

-30 + 5x = 6 + 2x

solving for variable 'x'.

move all terms containing x to the left, all other terms to the right.

add '-2x' to each side of the equation.

-30 + 5x + -2x = 6 + 2x + -2x

combine like terms: 5x + -2x = 3x

-30 + 3x = 6 + 2x + -2x

combine like terms: 2x + -2x = 0

-30 + 3x = 6 + 0

-30 + 3x = 6

add '30' to each side of the equation.

-30 + 30 + 3x = 6 + 30

combine like terms: -30 + 30 = 0

0 + 3x = 6 + 30

3x = 6 + 30

combine like terms: 6 + 30 = 36

3x = 36

divide each side by '3'.

x = 12

simplifying

x = 12

this should .

i believe that the answer is y+6=1/3(x+2)

it is rigid.; it is isometric. ; the size is preserved.

step-by-step explanation:

a translation is called an isometry; these are transformations that preserve congruence between pre-images and images.

they are also called rigid transformations, as the only thing that can happen to a pre-image is that it is moved or turned, not stretched or shrunk.

since congruence is preserved, the size is preserved.