there are 5 more than twice as many students taking Algebra 1 then taking algebra 2. If there are 44 students taking Algebra 2, what is the least number of students who could be taking Algebra 1? The least number of students is?

93

Step-by-step explanation:

Key :

A1 = Algebra 1

A2 = Algebra 2

Alright so basically lets first look at the info they gave us :

We have 5 more than twice as many students taking A1 than we do A2.

We have 44 students taking A2.

And we need to find the least amount of students that could be taking A1.

So we need to take the amount of students taking A2 (44) and double it to find the amount taking A1.

So we can do 44 x 2 = 88 to get this.

But the problem also states there is 5 more then twice the number of students taking A2.

So we have that 88 but now we just need to add 5 to make up for them telling us that in the problem.

So :

88 + 5 = 93

Our final answer and least amount of students taking A1 is 93 students.

93 students

Step-by-step explanation:

44 x 2 = 88

88 + 5 = 93

4/6 = 2/3

so it should take 3/3 hours per man. so 9 hours is the answer 3*3 =9

step-by-step explanation:

step-by-step explanation:

let

we know that

the y-intercept is the y-coordinate of the point when the value of x is equal to zero

so

the y-coordinate of the point a is the y-intercept

the answer part a) is

the value of y-intercept is

part b) find the slope m

we know that

the value of the slope is equal to

substitute the values

therefore

the answer part b) is

the value of the slope is equal to

the general answer is

the slope is

the value of y-intercept is