The triangular prism above has been created with two equilateral triangles and three congruent rectangles the height of the triangle is 3.5 inches find the surface area of the triangular prism

108 inches square.

Step-by-step explanation:

Here

base= b= 4 inches

height = h=w=  3.5 inches

and length = l= 9  inches

The surface area is the total area of all the sides of the prism. So the area of the 2 triangles is given by

Area of the 2 Δs= b* h= 4*3.5=  13.5 inches square

Area of the 3 rectangles = l*w(3)= 3( 9*3.5)= 94.5  inches square.

Total area = 13.5 + 94.5 = 108 inches square

This can be found by applying another formula.

Surface area of the triangular prism = bh + ( s1+s2+s3) H

                                                         = 4*3.5 + (9+9+9)3.5

                                                          = 13.5 + 94.5= 108 inches square.

where H is the width of the recatngles which is equal to the height of the triangles.

34.5 cm

step-by-step explanation:

generally for a circular segment of angle, θ° and radius r

arc length

= (θ/360) x circumference

= (θ/360) x 2πr

in our case, θ = 60°, π=3.142 and r = 33 cm

substitute into above formula

arc length

= (60/360) x 2(3.142)( 33) = 34.5 cm

the answer is a if my teacher taught me correct