A triangular flower bed with sides 11 ft, 13 ft and 17 ft is filled 2 feet deep with compost that has a density of 13.2 lbs/ft2. How much willthe compost weigh that fills this flower bed?

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↓Answer↓

The length of a Triangular flower bed is 11 ft. less than 3 times its width. The area of the bed is 20ft^2. Find the dimensions of the flower bed.

let width be x

three times width =3x

length = 3x-11

x(3x-11)=20

3x^2-11x-20=0

3x^2-15x+4x-20=0

3x(x-5)+4(x-5)=0

(3x+4)(x-5)=0

x=5 width

width is 5 feet

length = 3x-11

=3*5 -11

=4 feet length

Hope this helped ya!

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dd

step-by-step explanation:

dd

answer:

your answer is: c. 196 7/8 in^3.