Graph the parabola. y=(x-3)^2-1

Step-by-step explanation:

y = (x-3)²-1

This is the equation for an up-opening parabola with vertex (3,-1).

Find the x-intercepts:

0 = (x-3)²-1

(x-3)² = 1

x-3 = ±1

x = 4, 2

The graph crosses the x-axis at (4,0) and (2,0).

Find the y-intercept:

y = (0-3)²-1 = 8

The graph crosses the y-axis at (0,8).

Plot your four points (3,-1), (4,0), (2,0), (0,8). Draw an up-opening parabola through the points.

describing distributions is one of the key skills you’ll need to earn a high score on the ap statistics exam. if you need proof of this, just flip through some past exam questions, which can be found at the collegeboard website. you’ll notice that the first free response question is almost always a question requiring you to look at a graph and describe it.

step-by-step explanation: just trying to get points sorry : (

answer: b. f(x) = (x + 2)^3 (x^2 - 7x + 3)^4

step-by-step explanation:

polynomials always have as many roots as their order. this is a 4th order polynomial- hence 4 roots!

complex roots of polynomials always come in pairs. the quadratic equation has the "+/-" in that will alwaysgenerate m+ni amd m-ni, so 7-2i must be a root of this polynomial equation.

the order of the numerator and denominator are both 2. so the horizontal asymptote is y=a2/b2 =7

verticle asymptotes are the forbidden x-values. f(x) becomes undefined at x=-3 because this value will cause a zero denominator.

a graph of r(x) will have vertical asymptotes at ±1 because these values will make the denominator zero. so the domain of the function cannot include ±1.

you 're wlecome! : )

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