In ΔIJK, i = 74 inches, j = 23 inches and ∠K=20°. Find the area of ΔIJK, to the nearest square inch.

291in^2

Step-by-step explanation:

Using the formula

Area of the triangle = 1/2absin theta

A = 1/2ijsin<K

Given

i = 74in

j = 23in

<K = 20 degrees

Area = 1/2 * 74*23sin20

Area = 37*23sin20

Area = 852sin20

Area = 291.059in^2

Hence the area of the triangle to nearest square inch is 291in^2

b

step-by-step explanation:

answer

a,b, and d

explanation

a reflection angle is more than

but less than;

an angle that measures

is a reflex angle.(true)

an angle that measures less than

is acute.(true)

provided we are considering angles greater or equal to zero.

an acute angle lies in the range.

an obtuse angle is less than 180° but more than 90°

an angle that measures 300° is obtuse (false)

an angle that measures 65° is an acute angle.(true)