One number is 3 less than 4 times a second number. The difference of the first number and twice the second number is 7. What are the two numbers?

atq= let no.be x and y

x= 4y-3(1)

x-2y=7(2)

subtracting both eqn

x-x+2y=4y-3-7

2y=4y-10

-2y= -10

y=5 second no.

first no...x=7+2y=7+10=17first no

step-by-step explanation:

5×5×5+2(8)÷2(2)+3(3)

15+16÷4+9

31÷13

do 31÷13 and u will get ur answer