The local ranger station tracked and tagged 2,844 adult female black bears in a national park. A random sample of 9 adult female black bears from those tagged had an average body weight of 203 pounds with standard deviation 25 pounds. Which of the following is a point estimate for the population mean weight of all female black bears that are tagged? a. 9
b. 25/√9
c. 25
d. 203
e. 2,844

203

Step-by-step explanation:

Sample size, n = 9

Mean weight, m = 203

Standard deviation = 25

Point estimate for the population mean weight of all black bears that are tagged `

The point estimate of the population mean ;

ΣX / n

Sum of sample / sample size ;

This is the mean value formula for the sample.

However, since it has been given in the question that, sample mean weight value = 203 ; then the point estimate of the population mean weight = 203

answer: c, the green line

step-by-step explanation:

there is no black line, eliminate b.

simple interest implies periodic payments, but the red line shows no payments, eliminate d.

simple interest has equal payments. if paid say every day, the graph is about a straight line (actually a stairstep).

the yellow line is not straight, eliminate a.

check: the green line is straight, answer is c.

simple interest with positive interest rate gives a straight line sloping up to the right. green line:

g(t) = $100 + ($200-$100) ÷ (20 years) × (t years)

= $100 + (4%/year) × ($100)(t years)

incidentally, the yellow line curving upward represents continuously compounded interest

y = $100 × 2^(t years / (14 assuming the yellow line hits $200 at 14 years. 2^0 is 1, so y(0) = $100; 2^(14/14) is 2, so y(14) = $200.

yes

step-by-step explanation:

yes