Mathematics, 19.02.2021 18:00 leannamat2106
I need help with math if you don't know the answer get out of the question and don't answer it and give the wrong answer or some link or even say "I don't know" or anything like that it's not fair to me cause it a waste of my points I will report your if you do that :) have a nice day and stay safe
Answers: 3
Mathematics, 21.06.2019 20:40
The graph of a function f(x)=(x+2)(x-4). which describes all of the values for which the graph is negative and increasing? all real values of x where x< -2 all real values of x where -2
Answers: 2
Mathematics, 22.06.2019 00:30
I've been working on this for a few days and i just don't understand, it's due in a few hours. you. the direction of a vector is defined as the angle of the vector in relation to a horizontal line. as a standard, this angle is measured counterclockwise from the positive x-axis. the direction or angle of v in the diagram is α. part a: how can you use trigonometric ratios to calculate the direction α of a general vector v = < x, y> similar to the diagram? part b suppose that vector v lies in quadrant ii, quadrant iii, or quadrant iv. how can you use trigonometric ratios to calculate the direction (i.e., angle) of the vector in each of these quadrants with respect to the positive x-axis? the angle between the vector and the positive x-axis will be greater than 90 degrees in each case. part c now try a numerical problem. what is the direction of the vector w = < -1, 6 > ?
Answers: 1
Mathematics, 22.06.2019 02:30
Will’s boss has asked him to compile the credit scores of everyone in his department. the data that will collected is shown in the table below. what is the mode of the credit scores in will’s department? (round to the nearest whole point, if applicable.) 634 667 644 892 627 821 857 703 654 a. 667 b. 722 c. 627 d. there is no mode in this group.
Answers: 1
Mathematics, 22.06.2019 03:30
Is a triangle with sides of length 6ft, 21 ft, 23 ft. a right triangle?
Answers: 1
I need help with math if you don't know the answer get out of the question and don't answer it and g...
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