An object is launched at 24.5 meters per second from a platform that is 68.6 meters tall. The equation for the object's height in meters, h, at seconds after the launch is -4.9 + 2 + 24.5t + 68.6 •To find the number of seconds it will take the object to hit the ground after it is thrown, h must be set equal to 0: True or False?
•If h is set equal to 0, then t = 0 is a solution to the equation: True or False?
•The object will hit the ground at t=7 seconds: True or False?​

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb

y=-2.5x+12.5

step-by-step explanation:

5y=2x+10

y=0.4x+2

slope=-2.5

5=-2.5*3+b

b=12.5

step-by-step explanation:

x-intercept:

(

−

1

+

√

7

,

0

)

,

(

−

1

−

√

7

,

0

)

y-intercept:

(

0

,

−

6

)

the given 6 = w/p is equivalent to 6p = w, where w is the total area of the walls and p is the area covered by a single can of paint.

knowing that 6 cans of paint will be needed, 6p = w becomes 6(6) = w = 36.   this tells us that the total area to be painted is 36 square units.