Two numbers have a difference of 13. The sum of twice one number and 3 times the other number is 1. Write a system of equations and solve the system to find the two numbers. You need not show 7 steps for this problem. Just show the system, solve the system, and write the two numbers.

first number = 8

second number = -5

Step-by-step explanation:

Let

x = first number

y = second number

Two numbers have a difference of 13.

x - y = 13

The sum of twice one number and 3 times the other number is 1

2x + 3y = 1

x - y = 13 (1)

2x + 3y = 1. (2)

From (1)

x = 13 + y

Substitute into (2)

2x + 3y = 1.

2(13 + y) + 3y = 1

26 + 2y + 3y = 1

26 + 5y = 1

5y = 1 - 26

5y = -25

y = -25/5

y = -5

Substitute y = -5 into (1)

x - y = 13

x - (-5) = 13

x + 5 = 13

x = 13 - 5

x = 8

hey there!

12 is twice as much as 6 because 6 goes into 12 2 times.

since the rabbit is twice as tall, we should multiply the weight of the first rabbit, 0.25, by 2.

0.25 x 2 = 0.5

therefore, the 12 inch chocolate rabbit weighs 0.5 lb, or half a pound.

hope this !

answer is the third choice:

3x^5+4x^4+x^3+2x^2-10x-7=0

step-by-step explanation: