How do I do problems like this?​

m<1 = 62°

m<2 = 45°

m<3 = 24°

Step-by-step explanation:

Hi!

Let me walk you through it!

The first step is to find angle 1.

Angle 1 is supplementary with the angle 118°

So we do 180° - 118° = 62°

m<1 = 62°

Then we find angle 2.

There are two ways to do this

The sum of interior angles in a triangle is 180°

So we do 180° - (73 + 62°)

Open parenthesis:

180° - 73° - 62° = 45°

You can also use the exterior angle theorem

118° = 73° + m<2

Same to both sides:

45° = m<2

So

m<2 = 45°

Now, using this information, we can find angle measure 3.

Now we look at the big triangle. Again, there are two ways to do this.

First way:

m<1 + 49° + m<2 + m<3 = 180°

Plug in known-values

62° + 49° + 45° + m<3 = 180°

Combine like terms:

156° + m<3 = 180°

Same to both sides:

m<3 = 24°

Second way:

Exterior angle theorem.

118° = m<2 + m<3 + 49°

Plug in known-values:

118° = 45° + m<3 +49°

Combine like terms:

118° = 94° + m<3

Same to both sides:

24° = m<3

So m<3 = 24°

There you go! You just need to take it step-by-step and you can get the answer. Be open-minded, don't just try to go for a certain angle, see what you can do, and work from there. It all comes together at the end.

Let me know if you have any questions, have a good day!

since the airplane is moving with constant speed then the distance travelled can be calculated by x=u*t

in km/h would be:

x=640*3.5=2.240 km

in m/s would be:

u=640 km/h= 640.000 m/h =640.000/ 3600 m/s =177.8 m/s

t= 3.5 h= 3.5 * 3600 s=12.600 s

then x=u*t= 177.8*12.600= 2.240.280 m