Mathematics, 20.02.2021 01:00 thisusernameistaken2

Holly is earning money to buy a new bike. Her parents give her $20 to start and she sells lemonade for $1.50 a cup. a. write a linear equation in slope intercept form for hollys money b. how mnay lemonades would holly have to sell to earn $250? c. Explain how you would graph the equation from part A on a coordinate plane PLEASE I NEED HELP ASAP!
Posted on Feb 19 4pm

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Answer from: persis52

250= 1.50x + 20

Step-by-step explanation:

here 250 is the goal. 1.50 is how much she makes for a cup and x is the number of times to get x much. with how much her parents gave is 20. so we add the money her parents give and 1.50 times x to know the money shegets from all the lemonade selling. graphing the equation but I cant do it on here

God Bless :>

Answer from: EatsChiken

a. y = c1.50 + 20

b. She would have to sell 167 cups to earn $250.50

c. im not sure on that sorr

Answer from: Quest

step-by-step explanation:

i think something is missing in your question because y-1=(x-12) would not pass through the point (-4,-3). because if you replace x by -4 your are supposed to find y=-3 which is not the case her. if you replace x by -4 you find =-15.

i assume the right equation is y-1=1/4*(x-12) because this one is passing through both your points (if you are interested to know how i found that out i can tell you).

in this equation if i replace x by -4 i find y=-3 and if i replace x by 12, i find y=1 so the line representing this equation is passing through those 2 points.

then the standard form of the equation is finding an expression of y in function of x

y-1=1/4*(x-12)

y=x/4-3+1

y=x/4-2

hope that .

do you confirm there was a mistake in the question?

Answer from: Quest

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

$x^2-2x+y^2-6y=26$

we now create space between the x and y terms with parenthesis.

$(x^2-2x)+(y^2-6y)=26$

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

$\frac{-2}{2} =(-1)^{2} =1$

$\frac{-6}{2} =(-3)^{2} =9$

we add the squares to both sides.

$(x^2-2x+1)+(y^2-6y+9)=26+1+9$

simplify.

$(x^2-2x+1)+(y^2-6y+9)=36$

and write the quadratics in factored form.

$(x-1)^{2} +(y-3)^{2} =36$

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.

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