Two triangles are cut from a rectangle to form a trapezoid. What is the ratio of the area of the trapezoid to the combined area of the triangles? A 18:54 C 54:18 B 18:72 D 72:18 12 in group of students is painting a background piece​

The image showing the trapezoid is missing, so i have attached it.

C 54:18

Step-by-step explanation:

Formula for area of trapezoid is;

A_trap = ½(sum of parallel sides) × height = ½(12 + (12 - (3 + 3))) × 6

A_trap = ½(12 + 6) × 6

A_trap = 54 in²

Combined area of triangle:

A_tria = 2 × ½ × 3 × 6 = 18 in²

Thus;

A_trap:A_tria = 54 in²:18 in² = 54:18

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet