What is a point-slope equation of the line with slope -12 that goes through the point (5,3)? A. y + 3 = 12 ( x + 5)
B. y - 3 = -12 ( x -5 )
C. y - 3 = 12 ( x - 5)
D. y + 3 = -12 ( x + 5 )

Step-by-step explanation:

Equation of a straight line is given by Y=MX+C

GIVEN POINTS (5, 3) and gradient -12, therefore

in the form of y=mx+c to get the constant, it will be 3=-12(5)+c

3=-60+c

3+60=c

c=63

y=mx+c

y=-12x+63

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